Question

At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one?

Answer 1

Let s = rate of rotation
Let r = radius of earth = 6,400km
Then solving (s^2) r = g will give the desired rate, from which length of day is inferred.
People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.

Answer 2

Thanks

Answer 3

2 days

Answer 4

I think curved one is best because as the earth rotate fast we must thrown like cure.
if straight line this not support by gravity

Answer 5

I'm not sure

Answer 6

Wow

Answer 7

I didn't get it. I need a full explanation. If any one can it please