At equilibrium, [S(CH2CH2Cl)2] = 350 M, [SCl2]=.325M, and [C2H4] =.273 M for the reaction below. SCl2 + 2C2H4 = S(CH2CH2Cl)2

Question

At equilibrium, [S(CH2CH2Cl)2] = 350 M, [SCl2]=.325M, and [C2H4] =.273 M for the reaction below.  SCl2 + 2C2H4 = S(CH2CH2Cl)2
What is the Kc?

DrBob222 · Accepted Answer

SCl2 + 2C2H4 = S(CH2CH2Cl)2' Kc = [S(CH2CH2Cl)2]/(C2H4)^2(SCl2) Substitute the numbers and solve for Kc.