At equilibrium at a certain temperature, the concentration of NzH3(g), H2(g) and N2(g) are 0.980 M, 1.53 M and 0.510, respectively. Calculate the value of kc for this reaction N2 (g)+3 H2(g)<<==>> 2NH3(g)

Answer 1

The equilibrium constant expression for the reaction is:

Kc = [NH3]^2/([N2][H2]^3)

Plugging in the equilibrium concentrations:

Kc = (0.980 M)^2/((0.510 M)(1.53 M)^3) = 0.456

Therefore, the value of Kc for this reaction at the given temperature is 0.456.