Asked by Casey
At car (1140-kg)traveling at 76.04 m/s and truck (12600-kg)traveling 6.88 m/s have a head-on collision and then stick together. What is their final common velocity (m/s)? (assume the car is going in the positive direction)
What is the cars' change in momentum in the above question (kg m/s)?
When I calculate the velocity of the truck, I get 22.9 m/s which is correct.
The formula that I am using to find the common velocity is
pi= (velocity car)(mass car) - (velocity truck)(mass truck)
I then take the pi calculated and use it to find the final velocity
vf = pi/(mc+mt)
I get close to the right answer (-4.36) but should have been -4.42.
For the last question. I believe that I am using the wrong formula.
mc*(vf-vc)
The correct answer was -31100 but I get nowhere near this number.
Am I missing some key steps here?
What is the cars' change in momentum in the above question (kg m/s)?
When I calculate the velocity of the truck, I get 22.9 m/s which is correct.
The formula that I am using to find the common velocity is
pi= (velocity car)(mass car) - (velocity truck)(mass truck)
I then take the pi calculated and use it to find the final velocity
vf = pi/(mc+mt)
I get close to the right answer (-4.36) but should have been -4.42.
For the last question. I believe that I am using the wrong formula.
mc*(vf-vc)
The correct answer was -31100 but I get nowhere near this number.
Am I missing some key steps here?
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