Your umpteen posts have been removed.
Once you write up YOUR THOUGHTS, please re-post, and someone here will be happy to comment.
At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 16.0 N/m is set into oscillatory motion with an amplitude of 20.0 cm. It is observed that the maximum speed of the bunch of bananas is 39.6 cm/s. What is the weight of the bananas in newtons?
2 answers
Try using the fact that the maximum kinetic energy , (1/2)MVmax^2
is equal to the initial potential energy stored in the spring,
(1/2) k X^2.
Then solve for Vmax
k is the spring force constant, which you have been given. X is the starting (and maximum) deflection
is equal to the initial potential energy stored in the spring,
(1/2) k X^2.
Then solve for Vmax
k is the spring force constant, which you have been given. X is the starting (and maximum) deflection
0 answers