X = 810 m/s^2
Y = 910 m/s^2
m = 0.32 kg
F = ?
a^2 = X^2 + Y^2 = 810^2 + 910^2 =
1,484,200
a = 1218 m/s2.
F = m*a = 0.32 * 1218 = 390 N
At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 810 m/s2 and the vertical or y component of its acceleration is 910 m/s2. The ball's mass is 0.32 kg. What is the magnitude of the net force acting on the soccer ball at this instant?
1 answer