Question

At an air show, a jet plane has velocity components vx = 695 km/h and vy = 440 km/h at time 4.85s and vx= 933km/h and vy = 465 km/h at time 7.12 s. For this time interval, find (a) the x and y components of the plane’s average acceleration and (b) the magnitude and direction of its average acceleration

find (a) the x and y components of the plane’s average acceleration and (b) the magnitude and direction of its average acceleration
d) for this time interval, find the direction of its average acceleration?
=? counterclockwise from + x axis

im having a hard time solving this problem

and for question (a) fo x i got 104.8 i got that wrong plus i even rounded it to 150 still wroung

Answer 1

Xf = 933000 m/h / 3600 s = 259.2 m/s.
Xo = 695000 m/h / 3600s = 193.1 m/s.

Yf = 465000 m/h / 3600 s = 129.2 m/s.
Yo = 440000 m/h / 3600 s = 122.2 m/s.

HOR.: (a) a == Xf-Xo) / (Tf-To),
a=(259.2-193.1) / (7.12-4.85)=29.1m/s^2

VER.: a = (Yf-Yo) / (Tf-To),
a = (129.2-122.2)/(7.12-4.85)=3.08m/s^2

b. tanA = Y/X = 3.08 / 29.1 = 0.10597.
A = 6.05 Deg.
a(avg)=X/cosA=29.1 / cos6.05=29.3m/s^2
@ 6.05 Deg.,CCW.

Answer 2

NOTE: You forgot to change unit of velocity to m/s.