At a school play, one family bought 3 student tickets and 2 adult tickets for point $20.50. Another family bought 4 student tickets and 1 adult ticket for $19.00. What was the cost of one student ticket? $1.50 $2.50 $3.50 $3.90

Answer 1

Let's assume the cost of one student ticket is $x and the cost of one adult ticket is $y.

From the information given, we can form the following equations:

3x + 2y = 20.50 .....(1) (Family 1)

4x + y = 19.00 .....(2) (Family 2)

Multiplying equation (2) by 2, we get:

8x + 2y = 38.00 .....(3)

Now, subtracting equation (1) from equation (3), we get:

(8x + 2y) - (3x + 2y) = 38.00 - 20.50

Simplifying,

8x - 3x = 17.50

5x = 17.50

Dividing both sides by 5, we get:

x = 3.50

Therefore, the cost of one student ticket is $3.50.