I assume you want Kc and not Kp.
13.4 mol/3.8 = approx 3 but that's just an estimate. You can recalculate and use a more accurate number.
........2SO3 ==> 2SO2 + O2
I.......3.........0.....0
C......-2x........2x....x
E......3-2x.......2x....x
You are given mols SO2, convert that to M (which is x), evaluate 2x and 3-2x. plug those numbers into Kc expression and solve for Kc.
Post your work if you get stuck.
At a particular temperature, 13.4 mol of SO3 is placed into a 3.8-L rigid container, and the SO3 dissociates by the reaction given below.
2 SO3(g) <-> 2 SO2(g) + O2(g)
At equilibrium, 3.6 mol of SO2 is present. Calculate K for this reaction.
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