cool steam to 100ºC
condense steam to water
cool water to 80ºC
two specific heats (water and steam)
... one heat of vaporization
At a nuclear power plant, water at 6degress Celius from a nearby lake is used in a heat exchange to condense spent steam at a temperature of 115 degees C to water at 80 degrees C. If the cooling water returns to the lake at a temperature of 18 degrees C, what mass of lake water is needed per kilogram of steam?
My solution:
Q lost = - q gained
m x 4200 x (18-6) = - 1kg x 4280 x (80-115)
m= 147000/50400
m= 2.9kg
The right answer is 48kg. Thank you for your help
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