at a museum, adult admission is $15. and children admissions is $6.50. during one day, a total of 2300 adult and children admissions were collected, and $27,700 was collected in fees. how many adult admissions were collected?

Answer 1

The algebra for this would be:

15a + 6.5c = 27700

where a is the number of adults and c is the number of children.

Answer 2

To expand on the previous response,

you have to solve through a system of equations:

a + c = 2300
15a + 6.5c = 27700

In the first equation, solve for C:

c = 2300 - a

Then substitute into the second equation:

15a + 6.5(2300 - a) = 27700

15a + 14950 - 6.5a = 27700

15a - 6.5a = 27700 - 14950

8.5a = 12750

8.5a/8.5 = 12750/8.5

a = 1500

Therefore, 1500 adult admissions were collected.

You can also substitute a = 1500 into the first equation:

c = 2300 - 1500
c = 800 children admissions sold.

Verify,

a + c = 2300

1500 + 800 = 2300 total admissions.

Best,
Farohw