P(6) = (0.45)^6*(0.55)^4*10!/(6!*4!) = 210*(8.304*10^-3)*(9.151*10^-2) = 0.1596
P(4) and P(5) will be higher, since the average number of spaghetti eaters out of 10 will be 4.5
at a local restaurant 45% of the customers order spaghetti. Estimate the probability that 6 of the next 10 customers will order spaghetti.
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