At a distance L equals to 400m from the traffic light, brakes are applied to a locomotive moving at a velociy VEquals to 54 km/hr. Determine the position of the locomotive relative to the traffic light l minute after application ofthe brakes if its acceleration is -0.3m/sec..

Answer 1

54 kph = 15 m/s

the locomotive stops in 50 s
... (15 m/s) / (0.3 m/s^2) = 50 s

the average velocity is 7.5 m/s
... (15 m/s + 0 m/s) / 2 = 7.5 m/s

7.5 m/s * 50 s = 375 m
... 25 m from the traffic light

Answer 2

given,
distance l=400m
u=54kmph
a=-0.3m/s2
u=15mps
v=u+at
t=v-u/a
t=15s
avrage velocity=7.5m/s
distance s = 7.5/15=375m
total distance=400m-375m=25m

Answer 3

Why 7.5how

Answer 4

Why 7.5 how

Answer 5

u = 54 x 5/18 = 15 m /s
a = - 0.3 m/s2
∴ v = u + at
0 = 15 – 0.3 t
t = 15 / 0.3 = 50 sec
After 50 second, locomotive comes in rest permanently.
∴ the distance of the locomotive from traffic light =
400 – 375 = 25 m

Answer 6

1 minute is 60s so you'll get 40m as relative distance