At a certain temperature the vapor pressure of pure benzene is measured to be 322. torr . Suppose a solution is prepared by mixing 138.g of benzene and 91.2g of heptane .

Question

At a certain temperature the vapor pressure of pure benzene is measured to be  322. torr . Suppose a solution is prepared by mixing 138.g of benzene and 91.2g of heptane  .

Calculate the partial pressure of benzene vapor above this solution. 3 sig figs!

Steps/equations are appreciated...!

DrBob222 · Answer

n benzene = grams/molar mass n heptane = grams/molar mass Xbenzene = n benzene/totalmols pbenzene = Xbenzene*P^o_benzene

Llama · Answer

llama