At a certain temperature, the reaction H2(g)+ Cl(g)=2HCl(g)has Kc = 5 x 10^8. If a reaction mixture at equilibrium contains 0.48 M of H2 and 0.23 M of Cl2, what is the concentration of HCl?

Question

I was wondering if I had to rearrange the equilibrium constant equation to work out the concentration of HCl (product).

Thanks for your help.

Answer 1

H2 + Cl2 ==> 2HCl
Kc = (HCl)^2/(H2)(Cl2)
You know Kc, (H2) and (Cl2). The only unknown is (HCl). Substitute and solve for that.