At a certain temperature, the reaction

Question

CO(g) + 2H2(g) <===> CH3OH(g) has Kc = 0.500. If a reaction mixture at equilibrium contains 0.00436 M CH3OH and 0.220 M H2, what is the equilibrium concentration of CO?

The answer is 0.280 M. I don't know how to get it.

Answer 1

sorry 0.180

Answer 2

Thanks for posting the correct answer. I was posting that the book had an error. Here is how you do it.
Kc = (CH3OH)/(H2)^2(CO)
Solve for (CO) = (CH3OH)/Kc(H2)^2
(CO) = (0.00436)/0.500*(0.22)^2
(CO) = 0.18017 which rounds to 0.180 to 3 s.f.

Answer 3

Thanks a lot! =) Very helpful.