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At a certain temperature, the Kp for the decomposition of H2S is 0.774.

H2S(g) <---> H2(g)+S(g)
Initially, only H2S is present at a pressure of 0.120 atm in a closed container. What is the total pressure in the container at equilibrium?

1 answer

.........H2S ==> H2(g) + S(g)
I......0.120......0......0
C........-x.......x......x
E......0.120-x....x......x

Kp = pH2*pS/pH2S
0.774 = (x)(x)/(0.120-x)

Solve for x and 0.120-x, then
Ptotal = pH2 + pS + pH2S
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