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At a certain temperature, the Kp for the decomposition of H2S is 0.734.Initially, only H2S is present at a pressure of 0.102 atm in a closed container. What is the total pressure in the container at equilibrium?

1 answer

Is this the equation? You should have given it.
.........H2S ==> H2 + S
I......0.102......0...0
C........-p.......p...p
E......0.102-p....p...p

Substitut the E line into the Kp expression and solve for p, then evaluate 0.102-p. Finally, add the partial pressures and the sum is the total pressure.
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