..........H2 + I2 --> 2HI
I........0.3...0.3.....0
C.......-x....-x.......x
E.....0.3-x..0.3-x.....x
Substitute the E line into the Kp expression and solve for x = p and 0.3-x
At a certain temperature, the equilibrium constant, K, for this reaction is 53.3.
H2(g)+I2(g)->2HI(g)
At this temperature, the reactants were placed in a container to react. If the partial pressures of H2 and I2 were each 0.300 bar initially, what is the partial pressure of HI at equilibrium?
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