Impulse = change of momentum
= m(v0-v1)
Average force = change of momentum / time
= m(v0-v1)/0.3 N (assuming m=0.15 kg)
at a ball game consider a baseball of mass m=0.15 that falls directly downward at a speed v=40m/s into the hands of a fan. what impulseft must be supplied to bring the ball to rest? if the ball is stopped in 0.3s, what is the average force of the ball on the catchers hand?
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