Let the speed of the cyclist heading north be x km/h and the speed of the cyclist heading south be (x-4) km/h.
From 9:00 am to 10:30 am, the first cyclist travels for 1.5 hours and the second cyclist travels for 1.5 hours as well.
The total distance traveled by the first cyclist is 1.5x km and the total distance traveled by the second cyclist is 1.5(x-4) km.
Given that they are 39 km apart at 10:30 am, we can set up the following equation:
1.5x + 1.5(x-4) = 39
Simplify the equation:
1.5x + 1.5x - 6 = 39
3x - 6 = 39
3x = 45
x = 15
Therefore, the speed of the cyclist heading north is 15 km/h and the speed of the cyclist heading south is (15-4) = 11 km/h.
at 9 on saturday morning two biciclysts heading in oppposite directions pass eachother on a bicycle path. the bcyclist heading north is riiding 4 km faster/hour then the biciclyist heading south. at 10 30 they are 39 km apart, find the two biciclyst rates
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