The distance between the two jets can be found using the Pythagorean theorem since they form a right triangle.
Distance = sqrt((64)^2 + (57)^2)
Distance = sqrt(4096 + 3249)
Distance = sqrt(7345)
Distance ≈ 85.7 miles
Therefore, the distance between the two jets is approximately 85.7 miles.
At 8:45 p.m., a jet is located 64 mi due east of a city. A second jet is located 57 mi due north of the city.
To the nearest tenth of a mile, what is the distance between the two jets?
Enter your answer as a decimal in the box.
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