At 60 celsius the value of Kw is 9.5x10^-14. considering this waht is the calculated value for the pOH of a 2.00x10^-3 M HCL solution at this temperature?

Question

the answer is 10.32

i do the -log and i get 11.31

please advice

Answer 1

I see what you did wrong. You used 1E-14 for Kw. The problem tells you it is 9.5E-14. Kw = 1E-14 @ 25 C but the problem is at 60 C and not 25 C.
(H^+)(OH^-) = 9.5E-14
(OH^-) = 9.5E-14/2E-3 = 4.75E-11
pOH = 10.32

Answer 2

ok thank you