At 462degrees, the reaction

(1) heat + 2 NOCl(g) <=====> 2 NO(g) + Cl2(g)
has an equilibrium constant, Keq = 8.0 x 10-2.

a) What is Keq at 462degrees for the reaction

2 NO(g) + Cl2(g) <=====> 2 NOCl(g)

1/Keq

may I ask how did you get this answer?

Keq for the reverse reaction is simply the reciprocal.

ok but What if the equation was then NOCl <=> NO + 1/2Cl2 ?

Then Keq for the reaction as written is sq rt original Keq.
It works this way.
2A + B2 ==> 2C Keq = 10
A + 1/2 B2 ==> C (Keq)1/2 = sq rt 10
4A + 2B2 ==> 4C (Keq)2 = 100
2C ==> 2A + B2 Keq = 0.1

Similar Questions
    1. answers icon 0 answers
  1. At 35°C, K = 1.6 10-5 mol/L for the following reaction.2 NOCl(g) 2 NO(g) + Cl2(g) Calculate the concentrations of all species
    1. answers icon 0 answers
  2. Hi, I was wondering if you could possibly help me with this chem question.For the relatively slow decomposition of NOCL into NO
    1. answers icon 1 answer
  3. Consider the following equilibrium.2 NOCl(g) ⇌ 2 NO(g) + Cl2(g) Determine Kc if 1.00 mol of NOCl(g) is initially placed in an
    1. answers icon 3 answers
more similar questions