At 450oC, the equilibrium constant Kc for the Haber-Bosch synthesis of ammonia is 0.16 for the reaction writeten as 3H2(g) + N2 (g)--><--2NH3(g) calculate the value of Kc for the same reaction written as 3/2H2(g) + 1/2N2(g)-->--<NH3(g)

Answer 1

3H2 + N2 ==> 2NH3 with Kc= 0.16

3/2H2 + 1/2N2 ==> NH3 is just 1/2 of the first equation; therefore, K'c = sqrt Kc or sqrt (0.16).