..........2BrCl ==> Br2 + Cl2
This done the same way as the earlier problem with SO2 --> SO3. These are equilibrium concns; therefore, substitute into Kc and calculate the one unknown. Post your work if you have trouble.
At 350 K, Kc = 0.142 for the reaction
2BrCl(g) *) Br2(g) + Cl2(g)
An equilibrium mixture at this temperature
contains equal concentrations of bromine and
chlorine, 0.069 mol/L. What is the equilib-
rium concentration of BrCl?
Answer in units of M
1 answer