At 35°C, K = 1.6 10-5 mol/L for the following reaction.

2 NOCl(g) 2 NO(g) + Cl2(g)
Calculate the concentrations of all species at equilibrium for each of the following original mixtures.
(a) 3.8 mol of pure NOCl in a 2.0-L flask
NOCl ___ M
NO ___M
Cl2 __ M

(b) 2.4 mol of NO and 1.2 mol of Cl2 in a 1.0-L flask
NOCl___ M
NO ___ M
Cl2 ___ M

Similar Questions
  1. Consider the following reaction:2NOCl(g) 2NO(g) + Cl2(g) Initially pure NOCl(g) is placed in a vessel at 3.00 atm. At
    1. answers icon 1 answer
  2. The following reaction exhibits the rate law: Rate = k[NO2]^2[Cl2].2NO(g)+Cl2(g)---->2NOCl (g) (a) Explain why the following
    1. answers icon 1 answer
  3. At 35 degrees Celcius,K = 1.6x10^-5 for the reaction: 2NOCl<--> 2NO + Cl2 If 2.0mol NOCl and 1.0mol Cl2 are placed into a 1.0-L
    1. answers icon 2 answers
    1. answers icon 3 answers
more similar questions