AT 25 DEGREES CELSIUS THE STANDARD ENTHALPY OF COMBUSTION OF GASEOUS PROPANE IS -2219.0 KJ PER MOLE OF PROPANE AND THER STANDARD ENTHALPY OF GASEOUS PORPYLENE IS -2058.3 KJ PER MOLE OF P[ROPYLENE. wHAT IS THE STANDARD ENTHALPY CHANGE FOR THE FOLLOWING REACTION C3H6 + H2 ---C3H8

Question

AT 25 DEGREES CELSIUS THE STANDARD ENTHALPY OF COMBUSTION OF GASEOUS PROPANE IS -2219.0 KJ PER MOLE OF PROPANE AND THER STANDARD ENTHALPY OF GASEOUS PORPYLENE IS -2058.3 KJ PER MOLE OF P[ROPYLENE.  wHAT IS THE STANDARD ENTHALPY CHANGE FOR THE FOLLOWING REACTION C3H6 + H2 ---C3H8

DrBob222 · Answer

The equation is
DHrxn = (n*DHfproducts) - (n*DHfreactants)
Balanced the equation (I think it is balanced as is). DH stands for delta H and DHf is delta Hformation. You can find DHf information for 25C probably in the back of your text. Note: This method does NOT use the information in the problem; i.e., it does not use the heat of combustion.