At 25 °C, only 1.9 g CaSO4 (MM = 136 g/mol) will dissolve in 2.00 L of water. Write the equilibrium

Question

expression and calculate the equilibrium constant for the reaction below.
CaSO4 (s) ⇋ Ca2+ (aq) + SO42- (aq)

Answer 1

Ksp = (Ca^+2)(SO4^-2)

Solubility CaSO4 = S = 1.9g/136 = ??mole and that in 2L is ??/2 = (S)
Then substitute the value for S into the Ka expression and solve for Ka.

Answer 2

nothing