solubility = 0.0570 mol/L = 0.0570M
........AB ==> A^+ + B^-
I......solid.. 0.....0
C......-x......x.....x
E......solid...x.....x
Ksp = (A^+)(B^-)
Ksp = (x)(x)
Substitute the value of x and calculate Ksp.
At 25 °C only 0.0570 mol of the generic salt AB is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C?
2 answers
All we know about salt AB is that the oxidation states of A and B are the same; therefore, it could be
A^+ and B^- or
A^2+ and B^2- or-
A^3+ and B^3-
but whatever it is Ksp is done the same way.
A^+ and B^- or
A^2+ and B^2- or-
A^3+ and B^3-
but whatever it is Ksp is done the same way.
1 answer