At 25°C, Kp = 2.910−3 for the following reaction.

NH4OCONH2(s) 2 NH3(g) + CO2(g)
In an experiment carried out at 25°C, a certain amount of NH4OCONH2 is placed in an evacuated rigid container and allowed to come to equilibrium. Calculate the total pressure in the container at equilibrium.

2 answers

I can't tell what the value of Kp is. I will assume you meant it to be 2.91E-3. BTW, you need to learn where the arrow key is too. The arrow tells us where the reactants stop and the products begin.

......NH4OCONH2(s) ==> 2NH3 + CO2
I.......solid...........0.......0
C.......solid...........2x.......x
E.......solid...........2x......x

Kp = p^2NH3*pCO2
Kp = (2x)^2(x)

Solve for x, 2x, and add the two pressures to find the total pressure.
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Resultados de traducción
At 25 ∘C, Kp = 2.9 × 10−3 for the reaction

NH4OCONH2 (s) ↽ −− ⇀2NH3 (g) + CO2 (g)

In an experiment at 25 ∘C, a certain amount of NH4OCONH2 (s) is placed in an empty rigid container and allowed to reach equilibrium.

Calculate the partial pressures of each gas and the total pressure in the container at equilibrium.
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