N2 + O2 ==> 2NO
Kp = pNO^2/pN2*pO2 = 0.05
Set up an ICE chart.
initial:
NO = 0
N2 = 0.8
O2 = 0.2
change:
NO = 2x
N2 = -x
O2 = -x
equilibrium:
NO = 2x
N2 = 0.8-x
O2 = 0.2-x
Substitute into Kp and solve.
Post your work if you get stuck.
At 2200 degrees celsius,kp=0.050 for the reaction: n2(g)+O2(g) ->2NO(g)
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What is the partial pressure of NO in equilibrium with N2 and O2 that were placed in a flask at initial pressures of .80 and .20 atm, respectively?
3 answers
0.082
0.1857