at 1p.m. two trains, traveling towards each other, leave from towns that are 312 km apart. one train averages at most 82 km/h and the other at most 74 km/h. what is the earliest time for them to meet?

Answer 1

when they meet they both will have travelled the same time after 1:00 pm
distance covered by faster train === x
distance covered by slower train == 312-x
time = distance/rate

x/82= (312-x)/74
solve for x

that will give you the distance, from there you can find the time
add that time to 1:00 pm