Since V is constant, if the pressure doubles, so does the temperature. Algebraically,
PV=kT
125°C = 398°K
(345)V = k(398)
(690)V = kT
T/398 = 690/345
T = 796°K = 523°C
At 125 degrees Celsius, the pressure of a sample of He gas is 345 mmHg. At what temperature degrees Celsius will the pressure become 690 mm Hg, if the volume remains constant?
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