At 10:00 AM a truck started traveling from point A with a speed of 40mph. 3 hours and 10 minutes later a car started to drive from point A in the same direction with an average speed of 60mph. At what time will the car catch up with the truck?

Answer 1

At the catch-up point, they will have travelled the same distance.

Time taken by car ---- x hrs
time taken by truck ---- x + 19/6 hrs (which is 3 hrs, 10 min)

60x = 40(x+19/6)
60x = 40x + 380/3
20x = 380/3
x = 19/3 hrs or 6 hrs, and 20 minutes

Interpret my answer .

Answer 2

Truck: d1 = 40mi/h * 3.1667h = 126.67 mi. head-start.

126.67 + 40 * T = 60 * T.
20T = 126.67,
T = 6.33h = 6hrs, and 20 min.