At 1 atm, how much energy is required to heat 37.0g of H2O at -24.0 C to H2O at 155.0 C?

Answer 1

q1 = heat needed to heat ice at -24 to zero C.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial) where Tf is zero and Ti is -24

q2 = heat needed to change solid ice at zero to liquid water at zero.
q2 = mass ice x heat fusion.

q3 = heat needed to heat water at zero to water at 100 C.
q3 = mass water x specific heat H2O x (Tfinal-Tinitial) where Tf is 100 and Ti = 0.

q4 = heat needed to change liquid water at 100 C to steam at 100 C.
q4 = mass water x heat vaporization

q5 = heat needed to heat steam and raise temperature from 100 C to 155 C.
q5 = mass steam x specific heat steam x (Tfinal-Tinitial) where Tf is 155 and Ti is 100.

Total Q = sum of each q; i.e.,
Qtotal = q1 + q2 + q3 + q4 + q5