Assuming you are on Earth, where acceleration due to gravity is

9.81 meters/second2, and you have a pendulum with a cord that is 0.65 meters long, what is the period?

2 answers

T^2 = 4*pi^2*(L/g)
T^2 = 39.48(0.65/9.8). Solve for T.
Where else am i going to be, !@#$%^&?