Assuming that you have 0.4g of Y(OH)3, calculate the mass of of BaO2 required to react stoichiometrically (1Y:2Ba:3Cu) to produce YBa2Cu3O7.

Now calculate the mass of of CuO required to react stoichiometrically (1Y:2Ba:3Cu) to produce YBa2Cu3O7.

please help!!

.4gY(OH)3> moles Y(OH)3 > moles Y

Then you need twice that number of moles of BaO2 (1Y:2Ba:3Cu),

Take the moles of Y, multiply it by 3 to get the moles of Cu. Knowing the moles of Cu, you know the moles of CuO, convert that to grams.
I will be happy to critique your work.

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