Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5 C? The freezing point for pure water is 0.0 C and Kf is equal to 1.86 C/m.

Question

* Use Tf = Kf*i*m

Answer 1

i=2

m=gramsKNO3/(molmassKNO3*.275)

find grams KNO3 from your fourmula.