P,abs = P + pgh
P = (1.01*10^5 Pa) + (1025 kg/m^3)*(9.8 m/s^2)(15 m)
P = 101000 + 150675
P = 251675 Pa
Check the significant figures.
Hope this helps~ `u`
Assuming atmospheric pressure to be 1.01 x 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15.0m below the surface of the ocean?
Could you show me how to do this problem? Thank you.
2 answers
Verify that the atmospheric pressure at sea level is 1.o1×10pa