Assuming an element's half-life is 3.6 years. How much of 2 grams of the element would remain after 10.8 years?

Answer 1

k = 0.693/t_1/2
Substitute into the below equation.

ln(No/N) = kt
No = 2 g from the problem.
N = to be calculated (how much is left)
k from above.
t = 10.8 years.
Solve for N

Answer 2

.25

Answer 3

1.6