Assuming all volume measurements are made
at the same temperature and pressure, what
volume of hydrogen gas is needed to react
completely with 2.96 L of oxygen gas to pro-
duce water vapor?
Answer in units of L
6 answers
I thought you were working these the last day or so like a pro. What's the problem with this?
I was not working on these the other day. I think I might know how to do this problem, but can you explain it so i can be sure?
Yes I can; however, if you thought about it, it would be easier for you to show what you did and let me check it. That way I can see if you are doing anything wrong. However, just this once.
2H2 + O2 ==> 2H2O
When everything is in the gaseous state we may use L as if volume = mols.
Therefore, 2.96L x (1 mol O2/2 mols H2) = 2.96 x 1/2 = 1.48 L O2 needed.
2H2 + O2 ==> 2H2O
When everything is in the gaseous state we may use L as if volume = mols.
Therefore, 2.96L x (1 mol O2/2 mols H2) = 2.96 x 1/2 = 1.48 L O2 needed.
I thought you were supposed to multiply 2.96 by 2 to get 5.92L. Why would you multiply it by .5 when you are trying to find out the volume of hydrogen gas?
Because I worked it wrong. I read the problem as having H2 and asking how much oxygen and not how much H2. I already had volume O2.
2.96 L O2 x (2 mol H2/1 mol O2) = 2.96 x 2 = ?
Sorry about that.
2.96 L O2 x (2 mol H2/1 mol O2) = 2.96 x 2 = ?
Sorry about that.
Thank you