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Assume you are performing the calibration step of Experiment 8 and you begin with 70 g of water at 20 oC and 70 g of water at 80 oC. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine the temperature of the mixed portions of water to be 45 oC. What is the heat capacity of the calorimeter
4 answers
Writeacher is correct. I never would have clicked on uah.
How much heat was gained by the cold water?
mass x specific heat x (Tfinal-Tinitial) = ??
How much was lost by the hot water?
mass x specific heat x (Tfinal-Tinitial) = ??
What's the difference? The difference is how much was absorbed by the calorimeter. Take the difference and divide by delta T to find cCal. You don't say what the initial T of the calorimeter was; perhaps it was 20, the same as the cold water. Perhaps it was something different but delta T will be Tfinal (45 C?) - Tinitial.
How much heat was gained by the cold water?
mass x specific heat x (Tfinal-Tinitial) = ??
How much was lost by the hot water?
mass x specific heat x (Tfinal-Tinitial) = ??
What's the difference? The difference is how much was absorbed by the calorimeter. Take the difference and divide by delta T to find cCal. You don't say what the initial T of the calorimeter was; perhaps it was 20, the same as the cold water. Perhaps it was something different but delta T will be Tfinal (45 C?) - Tinitial.
70
35. Source : MasteringChemistry. I got it wrong too many times.