Assume the sleigh and horse pulling it are on a level, horizontal surface.

Question

Given: mass of sleigh 475 kg / force of horse pulling sleigh 1.5×10^5 / coef. of kinetic friction .15 / coef. of static friction .20
a.) What is the normal force of the sleigh and its passengers?
b.) What is the maximum static friction force needed to get the sleigh to move?
c.) Once the sleigh is moving, what is the force of kinetic friction?
d.) What is the magnitude and direction of the net force when the sleigh is moving?
e.) What is the magnitude and direction of the acceleration of the sleigh?

Answer 1

a. M*g = 475 * 9.8 = 4655 N. = Wt. of sleigh. = Normal force(Fn).

b. Fs = u*Fn = 0.20 * 4655 =

c. Fk = uk*Fn = 0.15 * 4655 =

d. Fnet = Fh-Fk = 150,000-4655 =

Answer 2

e. Fnet = M*a.
a = Fnet/M.