To answer the questions, we need to assume some details about the subnet structure based on the given IP addresses.
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Calculate the DHCP Pool Size:
- The static IP addresses assigned are 192.168.0.1 (Linksys server) and 192.168.0.249 (Cisco server).
- Generally, a typical subnet for private IP addressing in the 192.168.x.x range is /24 (which corresponds to a subnet mask of 255.255.255.0).
- In this case, a /24 subnet contains IP addresses from 192.168.0.0 to 192.168.0.255. This amounts to a total of 256 IP addresses.
- Since both 192.168.0.1 and 192.168.0.249 are assigned as static IPs, those two addresses cannot be assigned out by the DHCP server.
Therefore:
- Total addresses available in the /24 subnet = 256
- Static addresses used = 2 (192.168.0.1 and 192.168.0.249)
- Hence, the number of IP addresses available in the DHCP pool = 256 - 2 = 254 IP addresses.
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Total Client Addresses:
- In a /24 subnet, the number of total addresses available (including the network and broadcast addresses) is calculated as:
- Network address: 192.168.0.0 (not usable for hosts)
- Broadcast address: 192.168.0.255 (not usable for hosts)
- Therefore, total usable addresses for clients is 256 (total) - 2 (network and broadcast) = 254 client addresses.
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First Possible IP Address in the DHCP Server's Pool:
- Since 192.168.0.1 is statically assigned, the DHCP pool for dynamic IP assignments starts after that. The next available IP address after 192.168.0.1 would be 192.168.0.2.
To summarize:
- Question 8: 254 IP addresses in the DHCP pool
- Question 9: 254 total client addresses
- Question 10: 192.168.0.2 as the first possible DHCP address