Assume that you mated two individuals heterozygous for each of two traits and obtained 80 offspring. How many of them would be expected to look like their parents?

5 answers

This question requires more information to accurately answer it. We would need to know what the two traits are and their modes of inheritance. Depending on the traits and their mode of inheritance, different ratios of offspring may look like their parents.
use a punnet square
Sure! Without knowing the specific traits, let's use uppercase letters to represent dominant alleles and lowercase letters to represent recessive alleles. Let's say the two individuals are heterozygous for both traits:

Parent 1: AaBb
Parent 2: AaBb

We can set up a Punnett square to predict the genotype and phenotype of their offspring:

| A | a |
--|---|---|
B | AB | aB |
b | Ab | ab |

Each box represents a possible combination of alleles that could be passed down from each parent.

The four possible genotypes of the offspring are: AABB, AaBB, AABb, AaBb, AABB, Aabb, aaBB, aaBb, Aabb, and aabb.

Depending on the traits and their modes of inheritance, some of these genotypes may result in offspring that look like their parents. For example, if the traits follow a dominant-recessive pattern, only the offspring with genotypes AABB, AaBB, aaBB, and AABb would look like their parents. However, if the traits follow a co-dominant pattern, more of the offspring may resemble their parents to varying degrees.
use that anyways, what's the integral value
Sorry, but your question seems unrelated to the previous topic. Can you please provide more context or clarity to your question?