logb(4) sqrt((x^7 y^2)/(z^4))
well, I'm not sure what logb(4) has to do with it, but
log(a^n) = n*log(a)
so,
log(√(x^7y^2/z^4)) = 1/2 (7logx + 2logy - 4logz)
= 7/2 logx + logy - 2logz
regardless of the base.
Assume that x, y, z and b are positive numbers. Use the properties of logarithms to write the expression logb(4) sqrt((x^7 y^2)/(z^4)) in terms of the logarithms x, y, and z.
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