Asked by Issie

Assume that x, y and z are positive numbers. Use the properties of logarithms to write the expression -2logb^(x-6)logb^y+1/7logb^z as the logarithm of one quantity.

answers:
a. logb z1/7 / x^2y^6
b. logb z 1/7 / x^6y^2
c. log x1/7 / y^2 z^6
d. logb z1/2 / x^7y^6
e. logo z1/6 / x^2y^7

the answer i got was -2logb(z)log(x-6)log(7y+1/7) but this is not one of the answers. can you help please?
Answered by luchia
you made a simplfying error i think
Answered by luchia
idk fo sure thorgh
Answered by Issie
do you know where I made the error or can you help me with the answer?
Answered by Steve
Since multiplying logs is not one of the usual operations, and none of the answers includes (x-6) I'd say you are in trouble from the start. I suspect that you were given

-2logb^x -6logb^y + 1/7 logb^z

That is choice (a), assuming the usual sloppiness with notation.
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