Assume that​ women's heights are normally distributed with a mean given by mu equals 63.4 in​, and a standard deviation given by sigma equals 1.8 in. Complete parts a and b.

Question

a. If 1 woman is randomly​ selected, find the probability that her height is between 62.7 in and 63.7 in.
The probability is approximately
nothing. ​(Round to four decimal places as​ needed.)

Answer 1

Did you sketch your curve to see exactly what the question is asking? Then you have to find the z-scores from both ends and use your z-score table (and remember that it reads less than) so you have to do the right most bound - the left most bound.
We will be happy to check your answer.

Answer 2

the height range is from 7/18 s.d. below the mean to 3/18 above the mean

a z-score table will show the portion of the population that lies in this range
... the portion is equivalent to the probability

Answer 3

To do this type of question, typically you will need a set tables showing standard deviation values. These were traditionally found in the back of textbooks. Many books these days no longer have these, since much more accurate on-line applets will do the same thing.

Here is one of the best: http://davidmlane.com/normal.html

Make sure you have selected "Area from a value" (the default)
Fill in your mean and SD, then click on 'between' , filling in these values