great webpage for your problem, just plug in the values that you have
http://davidmlane.com/hyperstat/z_table.html
Assume that women's heights are normally distributed with a mean given by u=64.6 in
and a standard deviation given by 0=2.8in.
a) If 1 woman is randomly selected, find the probability that her height is less than 65in.
b) If 49 women are randomly selected, find the probability that they have a mean height less than 65 in.
5 answers
a.
z = (65-64.6)/(2.8/sqrt(1))
z = 0.14
b.
z = (65-64.6)/(2.8/sqrt(49))
z = 1
z = (65-64.6)/(2.8/sqrt(1))
z = 0.14
b.
z = (65-64.6)/(2.8/sqrt(49))
z = 1
Assume that women's heights are normally distributed with a mean given by mu equals 64.9 inμ=64.9 in, and a standard deviation given by sigma equals 2.7 inσ=2.7 in. Complete parts a and b.
a. If 1 woman is randomly selected, find the probability that her height is between 64.264.2 in and 65.265.2 in.
The probability is approximately
0.14650.1465. (Round to four decimal places as needed.)
b. If 6 women are randomly selected, find the probability that they have a mean height between 64.264.2 in and 65.265.2 in.
The probability is approximately
a. If 1 woman is randomly selected, find the probability that her height is between 64.264.2 in and 65.265.2 in.
The probability is approximately
0.14650.1465. (Round to four decimal places as needed.)
b. If 6 women are randomly selected, find the probability that they have a mean height between 64.264.2 in and 65.265.2 in.
The probability is approximately
Assume that women's heights are normally distributed with a mean given by mu equals 62.3 inμ=62.3 in, and a standard deviation given by sigma equals 2.7 inσ=2.7 in.
(a) If 1 woman is randomly selected, find the probability that her height is less than 6363 in.
(b) If 4343 women are randomly selected, find the probability that they have a mean height less than 6363 in.
(a) If 1 woman is randomly selected, find the probability that her height is less than 6363 in.
(b) If 4343 women are randomly selected, find the probability that they have a mean height less than 6363 in.
Assume that women's heights are normally distributed with a mean given by mu equals inμ=62.6 and a standard deviation given by sigma equals inσ=2.4 in.
(a) If 1 woman is randomly selected, find the probability that her height is less than 63 in.
(b) If 36 women are randomly selected, find the probability that they have a mean height less than 63 in.
(a) The probability is approximately
nothing.
(Round to four decimal places as needed.)
(a) If 1 woman is randomly selected, find the probability that her height is less than 63 in.
(b) If 36 women are randomly selected, find the probability that they have a mean height less than 63 in.
(a) The probability is approximately
nothing.
(Round to four decimal places as needed.)